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Popular >

-4y^'+y=1

Solution

- 4 y^{^{'}} + y = 1

Solution

y = - e^{\frac{t + c _{1}}{4}} + 1

Solution steps

- 4 y^{'} (t) + y = 1

Solve separable ODE:

y = - e^{\frac{t + c _{1}}{4}} + 1

y = - e^{\frac{t + c _{1}}{4}} + 1

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Frequently Asked Questions (FAQ)

What is the solution for -4y^'+y=1 ?
The solution for -4y^'+y=1 is y=-e^{(t+c_{1})/4}+1