What is the derivative of 9e^x+2/(\sqrt[3]{x}) ?

The derivative of 9e^x+2/(\sqrt[3]{x}) is 9e^x-2/(3x^{4/3)}

What is the first derivative of 9e^x+2/(\sqrt[3]{x}) ?

The first derivative of 9e^x+2/(\sqrt[3]{x}) is 9e^x-2/(3x^{4/3)}

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9 e^{x} - \frac{2}{3 x ^{\frac{4}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (9 e^{x}) = 9 e^{x}

= 9 e^{x} - \frac{2}{3 x ^{\frac{4}{3}}}

\int_{- 2}^{1} (x - 8 ∣ x ∣) d x

f (x) = \frac{x}{2 x + 3}

\frac{d}{d x} (x^{2} - c x)

\frac{d}{d x} (\frac{3}{2 x ^{2}})

ln (x) \frac{d y}{d x} + \frac{y}{x} = x ln (x)

What is the derivative of 9e^x+2/(\sqrt[3]{x}) ?
The derivative of 9e^x+2/(\sqrt[3]{x}) is 9e^x-2/(3x^{4/3)}
What is the first derivative of 9e^x+2/(\sqrt[3]{x}) ?
The first derivative of 9e^x+2/(\sqrt[3]{x}) is 9e^x-2/(3x^{4/3)}