What is the solution for ln(x)(dy)/(dx)+y/x =xln(x) ?

The solution for ln(x)(dy)/(dx)+y/x =xln(x) is y=(x^2)/2-(x^2)/(4ln(x))+(c_{1})/(ln(x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

ln(x)(dy)/(dx)+y/x =xln(x)

ln (x) \frac{d y}{d x} + \frac{y}{x} = x ln (x)

y = \frac{x ^{2}}{2} - \frac{x ^{2}}{4 ln ( x )} + \frac{c _{1}}{ln ( x )}

Solution steps

ln (x) \frac{d y}{d x} + \frac{y}{x} = x ln (x)

Solve linear ODE:

y = \frac{x ^{2}}{2} - \frac{x ^{2}}{4 ln ( x )} + \frac{c _{1}}{ln ( x )}

y = \frac{x ^{2}}{2} - \frac{x ^{2}}{4 ln ( x )} + \frac{c _{1}}{ln ( x )}

\frac{d}{d x} ((3 - 5 x)^{5})

\frac{d}{d x} (\frac{x ^{4}}{x - 1})

x = \frac{12 - y ^{2}}{4}, x = y

y^{^{'}} x + 4 y x = 8, y (0) = 1

\int \frac{1}{( 1 + sin ^{2} ( x ) )} d x

What is the solution for ln(x)(dy)/(dx)+y/x =xln(x) ?
The solution for ln(x)(dy)/(dx)+y/x =xln(x) is y=(x^2)/2-(x^2)/(4ln(x))+(c_{1})/(ln(x))