What is the integral from 1 to infinity of 4/(x-1) ?

The integral from 1 to infinity of 4/(x-1) is diverges

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integral from 1 to infinity of 4/(x-1)

\int_{1}^{\infty} \frac{4}{x - 1} d x

diverges

Solution steps

\int_{1}^{\infty} \frac{4}{x - 1} d x

Compute the indefinite integral:

\int \frac{4}{x - 1} d x = 4 ln ∣ x - 1 ∣ + C

Compute the boundaries:

\int_{1}^{\infty} \frac{4}{x - 1} d x =

diverges

= diverges

800 x - 0.1 x^{2}

n = 1 \sum \infty \frac{9 n}{4 n + 9}

\frac{d}{d x} (\frac{2}{1 - 3 x})

x \to 0 lim (\frac{x}{sin ( 3 x )})

(- 1, 2), (- 4, - 1)

What is the integral from 1 to infinity of 4/(x-1) ?
The integral from 1 to infinity of 4/(x-1) is diverges