What is the derivative of 2/(1-3x) ?

The derivative of 2/(1-3x) is 6/((1-3x)^2)

What is the first derivative of 2/(1-3x) ?

The first derivative of 2/(1-3x) is 6/((1-3x)^2)

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\frac{d}{d x} (\frac{2}{1 - 3 x})

\frac{6}{( 1 - 3 x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2}{1 - 3 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{1 - 3 x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} ((1 - 3 x)^{- 1})

Apply the chain rule:

- \frac{1}{( 1 - 3 x ) ^{2}} \frac{d}{d x} (1 - 3 x)

= - \frac{1}{( 1 - 3 x ) ^{2}} \frac{d}{d x} (1 - 3 x)

\frac{d}{d x} (1 - 3 x) = - 3

= 2 (- \frac{1}{( 1 - 3 x ) ^{2}} (- 3))

Simplify

2 (- \frac{1}{( 1 - 3 x ) ^{2}} (- 3)) : \frac{6}{( 1 - 3 x ) ^{2}}

= \frac{6}{( 1 - 3 x ) ^{2}}

x \to 0 lim (\frac{x}{sin ( 3 x )})

(- 1, 2), (- 4, - 1)

y^{^{'}} + 4 y = cos (4 t)

\frac{\partial}{\partial y} (3 x^{2} y^{3})

\frac{1}{1 - x ^{2}}

What is the derivative of 2/(1-3x) ?
The derivative of 2/(1-3x) is 6/((1-3x)^2)
What is the first derivative of 2/(1-3x) ?
The first derivative of 2/(1-3x) is 6/((1-3x)^2)