What is the derivative of 800x-0.1x^2 ?

The derivative of 800x-0.1x^2 is 800-0.2x

What is the first derivative of 800x-0.1x^2 ?

The first derivative of 800x-0.1x^2 is 800-0.2x

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derivative of

800 x - 0.1 x^{2}

800 - 0.2 x

Solution steps

\frac{d}{d x} (800 x - 0.1 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (800 x) - \frac{d}{d x} (0.1 x^{2})

\frac{d}{d x} (800 x) = 800

\frac{d}{d x} (0.1 x^{2}) = 0.2 x

= 800 - 0.2 x

n = 1 \sum \infty \frac{9 n}{4 n + 9}

\frac{d}{d x} (\frac{2}{1 - 3 x})

x \to 0 lim (\frac{x}{sin ( 3 x )})

(- 1, 2), (- 4, - 1)

y^{^{'}} + 4 y = cos (4 t)

What is the derivative of 800x-0.1x^2 ?
The derivative of 800x-0.1x^2 is 800-0.2x
What is the first derivative of 800x-0.1x^2 ?
The first derivative of 800x-0.1x^2 is 800-0.2x