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Popular >

area x-y^2=0,x+2y^2=3

Solution

area

x - y^{2} = 0, x + 2 y^{2} = 3

Solution

No Solution

Solution steps

Isolate

y

for

x - y^{2} = 0 : y = x, y = - x

Isolate

y

for

x + 2 y^{2} = 3 : y = \frac{3 - x}{2}, y = - \frac{3 - x}{2}

f_{1} (x) = x

f_{2} (x) = - x

To find the intersection points solve

f_{i} (x) = f_{j} (x)

x = - x : x = 0

x = \frac{3 - x}{2} : x = 1

x = - \frac{3 - x}{2} :

No Solution for

x \in R

- x = \frac{3 - x}{2} :

No Solution for

x \in R

- x = - \frac{3 - x}{2} : x = 1

\frac{3 - x}{2} = - \frac{3 - x}{2} : x = 3

Curves not bounded

= No Solution

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Frequently Asked Questions (FAQ)

What is area x-y^2=0,x+2y^2=3 ?
The answer to area x-y^2=0,x+2y^2=3 is No Solution