What is (\partial)/(\partial x)(x^2y^2z^2) ?

The answer to (\partial)/(\partial x)(x^2y^2z^2) is 2xy^2z^2

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(\partial)/(\partial x)(x^2y^2z^2)

\frac{\partial}{\partial x} (x^{2} y^{2} z^{2})

2 x y^{2} z^{2}

Solution steps

\frac{\partial}{\partial x} (x^{2} y^{2} z^{2})

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{2} z^{2} \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= y^{2} z^{2} \cdot 2 x^{2 - 1}

Simplify

= 2 x y^{2} z^{2}

f (x) = 7 x + 4, (3, 5)

\frac{d}{d x} (cot^{2} (x) csc (x))

\int x sin (6 x^{2} + 2) d x

\int \frac{1}{x ^{2} yz} d x

ln (4 - 3 x)

What is (\partial)/(\partial x)(x^2y^2z^2) ?
The answer to (\partial)/(\partial x)(x^2y^2z^2) is 2xy^2z^2