What is the tangent of f(x)=sqrt(7x+4),(3,5) ?

The tangent of f(x)=sqrt(7x+4),(3,5) is y= 7/10 x+29/10

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tangent of f(x)=sqrt(7x+4),(3,5)

tangent of

f (x) = 7 x + 4, (3, 5)

y = \frac{7}{10} x + \frac{29}{10}

Solution steps

Find the slope of

f (x) = 7 x + 4 : \frac{df ( x )}{d x} = \frac{7}{2 7 x + 4}

Compute the slope of

f (x) = 7 x + 4

(3, 5) : m = \frac{7}{10}

Find the line with slope m=

\frac{7}{10}

and passing through

(3, 5) : y = \frac{7}{10} x + \frac{29}{10}

y = \frac{7}{10} x + \frac{29}{10}

\frac{d}{d x} (cot^{2} (x) csc (x))

\int x sin (6 x^{2} + 2) d x

\int \frac{1}{x ^{2} yz} d x

ln (4 - 3 x)

x y^{2} y^{^{'}} = x + 3

What is the tangent of f(x)=sqrt(7x+4),(3,5) ?
The tangent of f(x)=sqrt(7x+4),(3,5) is y= 7/10 x+29/10