What is the solution for (dr}{dθ}=\frac{r^2)/θ ,r(1)=2 ?

The solution for (dr}{dθ}=\frac{r^2)/θ ,r(1)=2 is r(θ)=-2/(2ln(θ)-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dr}{dθ}=\frac{r^2)/θ ,r(1)=2

\frac{d r}{d θ} = \frac{r ^{2}}{θ}, r (1) = 2

r (θ) = - \frac{2}{2 ln ( θ ) - 1}

Solution steps

\frac{d r}{d θ} = \frac{r ^{2}}{θ}

Solve separable ODE:

r (θ) = - \frac{2}{2 ln ( θ ) - 1}

r (θ) = - \frac{2}{2 ln ( θ ) - 1}

\int \frac{x ^{2}}{8} d x

y = \frac{5}{x}, (\frac{1}{2}, 10)

\int x^{2} sin (θ) d x

\int \frac{7 x ^{2}}{( 225 + x ^{2} ) ^{2}} d x

What is the solution for (dr}{dθ}=\frac{r^2)/θ ,r(1)=2 ?
The solution for (dr}{dθ}=\frac{r^2)/θ ,r(1)=2 is r(θ)=-2/(2ln(θ)-1)