What is the tangent of y= 5/x ,(1/2 ,10) ?

The tangent of y= 5/x ,(1/2 ,10) is y=-20x+20

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tangent of y= 5/x ,(1/2 ,10)

tangent of

y = \frac{5}{x}, (\frac{1}{2}, 10)

y = - 20 x + 20

Solution steps

Find the slope of

y = \frac{5}{x} : \frac{d y}{d x} = - \frac{5}{x ^{2}}

Compute the slope of

y = \frac{5}{x}

(\frac{1}{2}, 10) : m = - 20

Find the line with slope m=

- 20

and passing through

(\frac{1}{2}, 10) : y = - 20 x + 20

y = - 20 x + 20

\int x^{2} sin (θ) d x

\int \frac{7 x ^{2}}{( 225 + x ^{2} ) ^{2}} d x

x \to 0 + lim ((5 x^{2}) (ln (x)))

y = \frac{x ^{2} - 1}{x ^{2} + x + 1}, at x = 1

\int 4 - 4 sin (x) + sin^{2} (x) d x

What is the tangent of y= 5/x ,(1/2 ,10) ?
The tangent of y= 5/x ,(1/2 ,10) is y=-20x+20