What is the limit as x approaches infinity of 1.04^x ?

The limit as x approaches infinity of 1.04^x is infinity

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limit as x approaches infinity of 1.04^x

x \to \infty lim (1.0 4^{x})

\infty

Solution steps

x \to \infty lim (1.0 4^{x})

Apply the common limit:

x \to \infty lim (a^{x}) = \infty, a > 1

= \infty

\int 5 x^{2} sin (8 x) d x

\frac{\partial}{\partial x} (6 x y^{3} z^{3} + 7 x yz)

\frac{d y}{d x} = 0.75 y

\frac{d y}{d x} + 6 x y^{4} = 0

\frac{d r}{d θ} = \frac{r ^{2}}{θ}, r (1) = 2

What is the limit as x approaches infinity of 1.04^x ?
The limit as x approaches infinity of 1.04^x is infinity