What is the derivative of (3x-2x^2^3) ?

The derivative of (3x-2x^2^3) is 3(3x-2x^2)^2(3-4x)

What is the first derivative of (3x-2x^2^3) ?

The first derivative of (3x-2x^2^3) is 3(3x-2x^2)^2(3-4x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} ((3 x - 2 x^{2})^{3})

3 (3 x - 2 x^{2})^{2} (3 - 4 x)

Solution steps

\frac{d}{d x} ((3 x - 2 x^{2})^{3})

Apply the chain rule:

3 (3 x - 2 x^{2})^{2} \frac{d}{d x} (3 x - 2 x^{2})

= 3 (3 x - 2 x^{2})^{2} \frac{d}{d x} (3 x - 2 x^{2})

\frac{d}{d x} (3 x - 2 x^{2}) = 3 - 4 x

= 3 (3 x - 2 x^{2})^{2} (3 - 4 x)

x \to \infty lim (1.0 4^{x})

\int 5 x^{2} sin (8 x) d x

\frac{\partial}{\partial x} (6 x y^{3} z^{3} + 7 x yz)

\frac{d y}{d x} = 0.75 y

\frac{d y}{d x} + 6 x y^{4} = 0

What is the derivative of (3x-2x^2^3) ?
The derivative of (3x-2x^2^3) is 3(3x-2x^2)^2(3-4x)
What is the first derivative of (3x-2x^2^3) ?
The first derivative of (3x-2x^2^3) is 3(3x-2x^2)^2(3-4x)