What is the derivative of-1/(2x) ?

The derivative of-1/(2x) is 1/(2x^2)

What is the first derivative of-1/(2x) ?

The first derivative of-1/(2x) is 1/(2x^2)

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\frac{d}{d x} (- \frac{1}{2 x})

\frac{1}{2 x ^{2}}

Solution steps

\frac{d}{d x} (- \frac{1}{2 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{1}{2} \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - \frac{1}{2} \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - \frac{1}{2} (- 1 \cdot x^{- 1 - 1})

Simplify

- \frac{1}{2} (- 1 \cdot x^{- 1 - 1}) : \frac{1}{2 x ^{2}}

= \frac{1}{2 x ^{2}}

\int \frac{5 - 4 x}{12 x - 4 x ^{2} - 8} d x

5 (ln (y)) y^{^{'}} - x^{7} y = 0

\int \frac{- 1}{1 + 9 x ^{2}} d x

(- 5, - 5), (0, - 7)

\frac{d}{d x} ((3 x - 2 x^{2})^{3})

What is the derivative of-1/(2x) ?
The derivative of-1/(2x) is 1/(2x^2)
What is the first derivative of-1/(2x) ?
The first derivative of-1/(2x) is 1/(2x^2)