What is the derivative of (t^6+26t^4-t^3+179)^{73} ?

The derivative of (t^6+26t^4-t^3+179)^{73} is 73(t^6+26t^4-t^3+179)^{72}(6t^5+104t^3-3t^2)

What is the first derivative of (t^6+26t^4-t^3+179)^{73} ?

The first derivative of (t^6+26t^4-t^3+179)^{73} is 73(t^6+26t^4-t^3+179)^{72}(6t^5+104t^3-3t^2)

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derivative of

(t^{6} + 26 t^{4} - t^{3} + 179)^{73}

73 (t^{6} + 26 t^{4} - t^{3} + 179)^{72} (6 t^{5} + 104 t^{3} - 3 t^{2})

Solution steps

\frac{d}{d t} ((t^{6} + 26 t^{4} - t^{3} + 179)^{73})

Apply the chain rule:

73 (t^{6} + 26 t^{4} - t^{3} + 179)^{72} \frac{d}{d t} (t^{6} + 26 t^{4} - t^{3} + 179)

= 73 (t^{6} + 26 t^{4} - t^{3} + 179)^{72} \frac{d}{d t} (t^{6} + 26 t^{4} - t^{3} + 179)

\frac{d}{d t} (t^{6} + 26 t^{4} - t^{3} + 179) = 6 t^{5} + 104 t^{3} - 3 t^{2}

= 73 (t^{6} + 26 t^{4} - t^{3} + 179)^{72} (6 t^{5} + 104 t^{3} - 3 t^{2})

x \to 0 lim ((1 + \frac{4}{x})^{x})

(0, 32), (100, 212)

\frac{d}{d t} (\frac{e ^{t}}{4 - 3 e ^{t}})

n = 0 \sum \infty \frac{n}{2 ^{n}} x^{n}

\int_{0}^{1} 1 - x d x

What is the derivative of (t^6+26t^4-t^3+179)^{73} ?
The derivative of (t^6+26t^4-t^3+179)^{73} is 73(t^6+26t^4-t^3+179)^{72}(6t^5+104t^3-3t^2)
What is the first derivative of (t^6+26t^4-t^3+179)^{73} ?
The first derivative of (t^6+26t^4-t^3+179)^{73} is 73(t^6+26t^4-t^3+179)^{72}(6t^5+104t^3-3t^2)