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Popular >

integral from 0 to 1 of 1-x

Solution

\int_{0}^{1} 1 - x d x

Solution

\frac{1}{2}

+1

Decimal Notation

0.5

Solution steps

\int_{0}^{1} 1 - x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 1 d x - \int_{0}^{1} x d x

\int_{0}^{1} 1 d x = 1

\int_{0}^{1} x d x = \frac{1}{2}

= 1 - \frac{1}{2}

Simplify

1 - \frac{1}{2} : \frac{1}{2}

= \frac{1}{2}

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(\partial)/(\partial x)(xyw)

\frac{\partial}{\partial x} (x y w)

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\frac{d}{d x} (cos (2 y) - 3 x^{2} y^{2})

integral of x(x^2+5)^3

\int x (x^{2} + 5)^{3} d x

integral from 0 to 1 of 1/((x^2+1)^2)

\int_{0}^{1} \frac{1}{( x ^{2} + 1 ) ^{2}} d x

derivative of (1-2x^3/((1+x^3)^2))

\frac{d}{d x} (\frac{1 - 2 x ^{3}}{( 1 + x ^{3} ) ^{2}})

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of 1-x ?
The integral from 0 to 1 of 1-x is 1/2