What is the slope ofintercept (0,32),(100,212) ?

The slope ofintercept (0,32),(100,212) is y= 9/5 x+32

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slope ofintercept (0,32),(100,212)

slope intercept

(0, 32), (100, 212)

y = \frac{9}{5} x + 32

Solution steps

Compute the slope

(0, 32), (100, 212) : m = \frac{9}{5}

Compute the

y

intercept:

b = 32

Construct the line equation

y = mx + b

where

m = \frac{9}{5}

and

b = 32

y = \frac{9}{5} x + 32

\frac{d}{d t} (\frac{e ^{t}}{4 - 3 e ^{t}})

n = 0 \sum \infty \frac{n}{2 ^{n}} x^{n}

\int_{0}^{1} 1 - x d x

\frac{\partial}{\partial x} (x y w)

\frac{d}{d x} (cos (2 y) - 3 x^{2} y^{2})

What is the slope ofintercept (0,32),(100,212) ?
The slope ofintercept (0,32),(100,212) is y= 9/5 x+32