What is the solution for y^{''}+5y^'-2y=0 ?

The solution for y^{''}+5y^'-2y=0 is y=c_{1}e^{((-5+sqrt(33))t)/2}+c_{2}e^{((-5-sqrt(33))t)/2}

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y^{''}+5y^'-2y=0

y^{^{''}} + 5 y^{^{'}} - 2 y = 0

y = c_{1} e^{\frac{( - 5 + 33 ) t}{2}} + c_{2} e^{\frac{( - 5 - 33 ) t}{2}}

Solution steps

y^{''} (t) + 5 y^{'} (t) - 2 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{( - 5 + 33 ) t}{2}} + c_{2} e^{\frac{( - 5 - 33 ) t}{2}}

y = c_{1} e^{\frac{( - 5 + 33 ) t}{2}} + c_{2} e^{\frac{( - 5 - 33 ) t}{2}}

\int \frac{1}{t ^{2} - 12 t + 40} d t

x \to 0 - lim \frac{1}{\frac{1}{x}}

(t^{6} + 26 t^{4} - t^{3} + 179)^{73}

x \to 0 lim ((1 + \frac{4}{x})^{x})

(0, 32), (100, 212)

What is the solution for y^{''}+5y^'-2y=0 ?
The solution for y^{''}+5y^'-2y=0 is y=c_{1}e^{((-5+sqrt(33))t)/2}+c_{2}e^{((-5-sqrt(33))t)/2}