What is the solution for (dy)/(dx)=1+e^{y-x+5} ?

The solution for (dy)/(dx)=1+e^{y-x+5} is y=-ln(-x-c_{1})+x-5

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(dy)/(dx)=1+e^{y-x+5}

\frac{d y}{d x} = 1 + e^{y - x + 5}

y = - ln (- x - c_{1}) + x - 5

Solution steps

\frac{d y}{d x} = 1 + e^{y - x + 5}

Solve using substitution:

y = - ln (- x - c_{1}) + x - 5

y = - ln (- x - c_{1}) + x - 5

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What is the solution for (dy)/(dx)=1+e^{y-x+5} ?
The solution for (dy)/(dx)=1+e^{y-x+5} is y=-ln(-x-c_{1})+x-5