What is (\partial)/(\partial h)(2pirh+pir^2) ?

The answer to (\partial)/(\partial h)(2pirh+pir^2) is 2pir

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(\partial)/(\partial h)(2pirh+pir^2)

\frac{\partial}{\partial h} (2 π r h + π r^{2})

2 π r

Solution steps

\frac{\partial}{\partial h} (2 π r h + π r^{2})

Treat

r

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial h} (2 π r h) + \frac{\partial}{\partial h} (π r^{2})

\frac{\partial}{\partial h} (2 π r h) = 2 π r

\frac{\partial}{\partial h} (π r^{2}) = 0

= 2 π r + 0

Simplify

= 2 π r

\frac{d}{d x} (\frac{2 y}{3 x ^{2} + 2 y ^{2}})

y^{^{''}} + 14 y^{^{'}} + 85 y = 0

\frac{3 x + 2}{4 x}

x \to 3 lim (x + 3 x - 3)

\int_{- 3}^{0} x 1 - x d x

What is (\partial)/(\partial h)(2pirh+pir^2) ?
The answer to (\partial)/(\partial h)(2pirh+pir^2) is 2pir