What is the integral of (sec^2(x))/(tan^2(x)) ?

The integral of (sec^2(x))/(tan^2(x)) is -cot(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (sec^2(x))/(tan^2(x))

\int \frac{sec ^{2} ( x )}{tan ^{2} ( x )} d x

- cot (x) + C

Solution steps

\int \frac{sec ^{2} ( x )}{tan ^{2} ( x )} d x

Simplify

\frac{sec ^{2} ( x )}{tan ^{2} ( x )} : csc^{2} (x)

= \int csc^{2} (x) d x

Use the common integral:

\int csc^{2} (x) d x = - cot (x)

= - cot (x)

Add a constant to the solution

= - cot (x) + C

x \to - 4 lim (3 x + 1)

\frac{\partial}{\partial h} (2 π r h + π r^{2})

\frac{d}{d x} (\frac{2 y}{3 x ^{2} + 2 y ^{2}})

y^{^{''}} + 14 y^{^{'}} + 85 y = 0

\frac{3 x + 2}{4 x}

What is the integral of (sec^2(x))/(tan^2(x)) ?
The integral of (sec^2(x))/(tan^2(x)) is -cot(x)+C