What is the first derivative of 3x-1 ?

The first derivative of 3x-1 is 3

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derivative of 3x-1

derivative of

3 x - 1

3

Solution steps

\frac{d}{d x} (3 x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) - \frac{d}{d x} (1)

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (1) = 0

= 3 - 0

Simplify

= 3

\frac{\partial}{\partial x} (ln (16 x^{2} - 13 y^{2}))

f (y) = 2 x^{2} + 3 x y + 4 y^{2} + 5 x + 6 y - 7

(x^{2} + y^{2} - 3) d x = (y + x y) d y, y (0) = 1

\frac{d y}{d x} = 1 + e^{y - x + 5}

\frac{d}{d y} (\frac{y}{3})