What is (\partial)/(\partial x)(ln(16x^2-13y^2)) ?

The answer to (\partial)/(\partial x)(ln(16x^2-13y^2)) is (32x)/(16x^2-13y^2)

Popular >

(\partial)/(\partial x)(ln(16x^2-13y^2))

\frac{\partial}{\partial x} (ln (16 x^{2} - 13 y^{2}))

\frac{32 x}{16 x ^{2} - 13 y ^{2}}

Solution steps

\frac{\partial}{\partial x} (ln (16 x^{2} - 13 y^{2}))

Treat

y

as a constant

Apply the chain rule:

\frac{1}{16 x ^{2} - 13 y ^{2}} \frac{\partial}{\partial x} (16 x^{2} - 13 y^{2})

= \frac{1}{16 x ^{2} - 13 y ^{2}} \frac{\partial}{\partial x} (16 x^{2} - 13 y^{2})

\frac{\partial}{\partial x} (16 x^{2} - 13 y^{2}) = 32 x

= \frac{1}{16 x ^{2} - 13 y ^{2}} \cdot 32 x

Simplify

\frac{1}{16 x ^{2} - 13 y ^{2}} \cdot 32 x : \frac{32 x}{16 x ^{2} - 13 y ^{2}}

= \frac{32 x}{16 x ^{2} - 13 y ^{2}}

f (y) = 2 x^{2} + 3 x y + 4 y^{2} + 5 x + 6 y - 7

(x^{2} + y^{2} - 3) d x = (y + x y) d y, y (0) = 1

\frac{d y}{d x} = 1 + e^{y - x + 5}

\frac{d}{d y} (\frac{y}{3})

x \to \infty lim (4 - \frac{1}{x})

What is (\partial)/(\partial x)(ln(16x^2-13y^2)) ?
The answer to (\partial)/(\partial x)(ln(16x^2-13y^2)) is (32x)/(16x^2-13y^2)