What is (\partial)/(\partial x)(e^{-4t}cos(pix)) ?

The answer to (\partial)/(\partial x)(e^{-4t}cos(pix)) is -pie^{-4t}sin(pix)

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(\partial)/(\partial x)(e^{-4t}cos(pix))

\frac{\partial}{\partial x} (e^{- 4 t} cos (π x))

- π e^{- 4 t} sin (π x)

Solution steps

\frac{\partial}{\partial x} (e^{- 4 t} cos (π x))

Treat

t

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= e^{- 4 t} \frac{\partial}{\partial x} (cos (π x))

Apply the chain rule:

- sin (π x) \frac{\partial}{\partial x} (π x)

= - sin (π x) \frac{\partial}{\partial x} (π x)

\frac{\partial}{\partial x} (π x) = π

= e^{- 4 t} (- sin (π x) π)

Simplify

= - π e^{- 4 t} sin (π x)

y = \frac{x}{x + 4}, (1, 0.2)

\frac{d}{d y} (- 2 y)

(1 - 3 sin (4 t))^{2}

3 x - 1

\frac{\partial}{\partial x} (ln (16 x^{2} - 13 y^{2}))

What is (\partial)/(\partial x)(e^{-4t}cos(pix)) ?
The answer to (\partial)/(\partial x)(e^{-4t}cos(pix)) is -pie^{-4t}sin(pix)