What is area x=8y^2,x=20+3y^2 ?

The answer to area x=8y^2,x=20+3y^2 is No Solution

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area x=8y^2,x=20+3y^2

area

x = 8 y^{2}, x = 20 + 3 y^{2}

No Solution

Solution steps

Isolate

y

for

x = 8 y^{2} : y = \frac{x}{2 2}, y = - \frac{x}{2 2}

Isolate

y

for

x = 20 + 3 y^{2} : y = \frac{x - 20}{3}, y = - \frac{x - 20}{3}

f_{1} (x) = \frac{x}{2 2}

f_{2} (x) = - \frac{x}{2 2}

To find the intersection points solve

f_{i} (x) = f_{j} (x)

\frac{x}{2 2} = - \frac{x}{2 2} : x = 0

\frac{x}{2 2} = \frac{x - 20}{3} : x = 32

\frac{x}{2 2} = - \frac{x - 20}{3} :

No Solution for

x \in R

- \frac{x}{2 2} = \frac{x - 20}{3} :

No Solution for

x \in R

- \frac{x}{2 2} = - \frac{x - 20}{3} : x = 32

\frac{x - 20}{3} = - \frac{x - 20}{3} : x = 20

Curves not bounded

= No Solution

\frac{d}{d x} ((x^{2} + 5 x + 2)^{7})

\int x^{3} 64 - x^{2} d x

\int x 81 + x^{2} d x

y = 2 x, y = 12 - x, y = 4 - x

f (x) = \frac{2 x - 1}{x + 9}, at x = 2

What is area x=8y^2,x=20+3y^2 ?
The answer to area x=8y^2,x=20+3y^2 is No Solution