What is the derivative of (x^2+5x+2^7) ?

The derivative of (x^2+5x+2^7) is 7(x^2+5x+2)^6(2x+5)

What is the first derivative of (x^2+5x+2^7) ?

The first derivative of (x^2+5x+2^7) is 7(x^2+5x+2)^6(2x+5)

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\frac{d}{d x} ((x^{2} + 5 x + 2)^{7})

7 (x^{2} + 5 x + 2)^{6} (2 x + 5)

Solution steps

\frac{d}{d x} ((x^{2} + 5 x + 2)^{7})

Apply the chain rule:

7 (x^{2} + 5 x + 2)^{6} \frac{d}{d x} (x^{2} + 5 x + 2)

= 7 (x^{2} + 5 x + 2)^{6} \frac{d}{d x} (x^{2} + 5 x + 2)

\frac{d}{d x} (x^{2} + 5 x + 2) = 2 x + 5

= 7 (x^{2} + 5 x + 2)^{6} (2 x + 5)

\int x^{3} 64 - x^{2} d x

\int x 81 + x^{2} d x

y = 2 x, y = 12 - x, y = 4 - x

f (x) = \frac{2 x - 1}{x + 9}, at x = 2

y = arccsc (4 x)

What is the derivative of (x^2+5x+2^7) ?
The derivative of (x^2+5x+2^7) is 7(x^2+5x+2)^6(2x+5)
What is the first derivative of (x^2+5x+2^7) ?
The first derivative of (x^2+5x+2^7) is 7(x^2+5x+2)^6(2x+5)