What is the integral of xsqrt(81+x^2) ?

The integral of xsqrt(81+x^2) is 1/3 (81+x^2)^{3/2}+C

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integral of xsqrt(81+x^2)

\int x 81 + x^{2} d x

\frac{1}{3} (81 + x^{2})^{\frac{3}{2}} + C

Solution steps

\int x 81 + x^{2} d x

Apply u-substitution

: \int u^{2} d u

= \int u^{2} d u

Apply the Power Rule

: \frac{u ^{3}}{3}

= \frac{u ^{3}}{3}

Substitute back

u = 81 + x^{2}

= \frac{( 81 + x ^{2} ) ^{3}}{3}

Simplify

\frac{( 81 + x ^{2} ) ^{3}}{3} : \frac{1}{3} (81 + x^{2})^{\frac{3}{2}}

= \frac{1}{3} (81 + x^{2})^{\frac{3}{2}}

Add a constant to the solution

= \frac{1}{3} (81 + x^{2})^{\frac{3}{2}} + C

y = 2 x, y = 12 - x, y = 4 - x

f (x) = \frac{2 x - 1}{x + 9}, at x = 2

y = arccsc (4 x)

\int tan^{3} (θ) d θ

x y^{^{''}} + 2 y^{^{'}} = 8 x^{2}

What is the integral of xsqrt(81+x^2) ?
The integral of xsqrt(81+x^2) is 1/3 (81+x^2)^{3/2}+C