What is the derivative of f(x)=sin(2x^3) ?

The derivative of f(x)=sin(2x^3) is cos(2x^3)*6x^2

What is the first derivative of f(x)=sin(2x^3) ?

The first derivative of f(x)=sin(2x^3) is cos(2x^3)*6x^2

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derivative of

f (x) = sin (2 x^{3})

cos (2 x^{3}) \cdot 6 x^{2}

Solution steps

\frac{d}{d x} (sin (2 x^{3}))

Apply the chain rule:

cos (2 x^{3}) \frac{d}{d x} (2 x^{3})

= cos (2 x^{3}) \frac{d}{d x} (2 x^{3})

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

= cos (2 x^{3}) \cdot 6 x^{2}

\int_{1}^{2} x x^{2} - 1 d x

x \to \infty lim (x - 3 x^{4})

11 x - \frac{8}{x}

\int \frac{1}{y ^{6}} - \frac{9}{y} d y

(4 a + 1)^{2}

What is the derivative of f(x)=sin(2x^3) ?
The derivative of f(x)=sin(2x^3) is cos(2x^3)*6x^2
What is the first derivative of f(x)=sin(2x^3) ?
The first derivative of f(x)=sin(2x^3) is cos(2x^3)*6x^2