What is the derivative of (4a+1)^2 ?

The derivative of (4a+1)^2 is 8(4a+1)

What is the first derivative of (4a+1)^2 ?

The first derivative of (4a+1)^2 is 8(4a+1)

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derivative of

(4 a + 1)^{2}

8 (4 a + 1)

Solution steps

\frac{d}{d a} ((4 a + 1)^{2})

Apply the chain rule:

2 (4 a + 1) \frac{d}{d a} (4 a + 1)

= 2 (4 a + 1) \frac{d}{d a} (4 a + 1)

\frac{d}{d a} (4 a + 1) = 4

= 2 (4 a + 1) \cdot 4

Simplify

= 8 (4 a + 1)

y^{^{''}} + 4 y^{^{'}} = 10 e^{t}

\frac{d}{d x} (\frac{e ^{4 x} + e ^{- 4 x}}{x})

2 x, x = 3

f^{^{''}} (x) = f (x)

\frac{d y}{d x} + 2 y = 7, y (0) = 1

What is the derivative of (4a+1)^2 ?
The derivative of (4a+1)^2 is 8(4a+1)
What is the first derivative of (4a+1)^2 ?
The first derivative of (4a+1)^2 is 8(4a+1)