What is the solution for (dy)/(dx)+2y=7,y(0)=1 ?

The solution for (dy)/(dx)+2y=7,y(0)=1 is y=-(5e^{-2x})/2+7/2

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(dy)/(dx)+2y=7,y(0)=1

\frac{d y}{d x} + 2 y = 7, y (0) = 1

y = - \frac{5 e ^{- 2 x}}{2} + \frac{7}{2}

Solution steps

\frac{d y}{d x} + 2 y = 7

Solve separable ODE:

y = - \frac{5 e ^{- 2 x}}{2} + \frac{7}{2}

y = - \frac{5 e ^{- 2 x}}{2} + \frac{7}{2}

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\int \frac{4 + 4 x}{1 + x ^{2}} d x

f (x) = \frac{2 x + 1}{x ^{2} + 2}

(- 2.2) (3.4)

\int (1 + x) e^{- x} d x

What is the solution for (dy)/(dx)+2y=7,y(0)=1 ?
The solution for (dy)/(dx)+2y=7,y(0)=1 is y=-(5e^{-2x})/2+7/2