What is the solution for ((e^x+e^{-x})dy)/(dx)=y^2 ?

The solution for ((e^x+e^{-x})dy)/(dx)=y^2 is y=-1/(arctan(e^x)+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((e^x+e^{-x})dy)/(dx)=y^2

\frac{( e ^{x} + e ^{- x} ) d y}{d x} = y^{2}

y = - \frac{1}{arctan ( e ^{x} ) + c _{1}}

Solution steps

\frac{( e ^{x} + e ^{- x} ) d y}{d x} = y^{2}

Solve separable ODE:

y = - \frac{1}{arctan ( e ^{x} ) + c _{1}}

y = - \frac{1}{arctan ( e ^{x} ) + c _{1}}

\frac{d}{d x} (\frac{1}{x ^{2} - 9})

\int 3 x e^{4 x} d x

\frac{d}{d x} (\frac{x}{( x ^{2} + 1 ) ^{\frac{1}{2}}} - 1)

s^{2} + t^{2}

What is the solution for ((e^x+e^{-x})dy)/(dx)=y^2 ?
The solution for ((e^x+e^{-x})dy)/(dx)=y^2 is y=-1/(arctan(e^x)+c_{1)}