What is the derivative of x/((x^2+1^{1/2)}-1) ?

The derivative of x/((x^2+1^{1/2)}-1) is 1/((x^2+1)^{3/2)}

What is the first derivative of x/((x^2+1^{1/2)}-1) ?

The first derivative of x/((x^2+1^{1/2)}-1) is 1/((x^2+1)^{3/2)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{x}{( x ^{2} + 1 ) ^{\frac{1}{2}}} - 1)

\frac{1}{( x ^{2} + 1 ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{x}{( x ^{2} + 1 ) ^{\frac{1}{2}}} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x}{( x ^{2} + 1 ) ^{\frac{1}{2}}}) - \frac{d}{d x} (1)

\frac{d}{d x} (\frac{x}{( x ^{2} + 1 ) ^{\frac{1}{2}}}) = \frac{1}{( x ^{2} + 1 ) ^{\frac{3}{2}}}

\frac{d}{d x} (1) = 0

= \frac{1}{( x ^{2} + 1 ) ^{\frac{3}{2}}} - 0

Simplify

= \frac{1}{( x ^{2} + 1 ) ^{\frac{3}{2}}}

s^{2} + t^{2}

\int e^{c o s (π x)} sin (π x) d x

n = 0 \sum \infty (n) sin (\frac{1}{n})

y^{^{'}} + a y - b = 0

\int \frac{5}{4 + 9 r ^{2}} d r

What is the derivative of x/((x^2+1^{1/2)}-1) ?
The derivative of x/((x^2+1^{1/2)}-1) is 1/((x^2+1)^{3/2)}
What is the first derivative of x/((x^2+1^{1/2)}-1) ?
The first derivative of x/((x^2+1^{1/2)}-1) is 1/((x^2+1)^{3/2)}