What is the integral from 0 to (3pi)/2 of 7|sin(x)| ?

The integral from 0 to (3pi)/2 of 7|sin(x)| is 21

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integral from 0 to (3pi)/2 of 7|sin(x)|

\int_{0}^{\frac{3 π}{2}} 7 ∣ sin (x) ∣ d x

21

Solution steps

\int_{0}^{\frac{3 π}{2}} 7 ∣ sin (x) ∣ d x

Eliminate Absolutes

= \int_{0}^{π} 7 sin (x) d x + \int_{π}^{\frac{3 π}{2}} 7 (- sin (x)) d x

\int_{0}^{π} 7 sin (x) d x = 14

\int_{π}^{\frac{3 π}{2}} 7 (- sin (x)) d x = 7

= 14 + 7

Simplify

= 21

f (x) = e^{x}, g (x) = cos (x), x = 0, x = \frac{π}{2}

y = x^{2} - 3 x, y = x

\int_{0}^{2} x (1 - x) d x

x \to - \infty lim (1 + e^{x})

\frac{d}{d x} (y^{2} + x)

What is the integral from 0 to (3pi)/2 of 7|sin(x)| ?
The integral from 0 to (3pi)/2 of 7|sin(x)| is 21