What is the limit as x approaches-infinity of 1+e^x ?

The limit as x approaches-infinity of 1+e^x is 1

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limit as x approaches-infinity of 1+e^x

x \to - \infty lim (1 + e^{x})

1

Solution steps

x \to - \infty lim (1 + e^{x})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to - \infty lim (1) + x \to - \infty lim (e^{x})

x \to - \infty lim (1) = 1

x \to - \infty lim (e^{x}) = 0

= 1 + 0

Simplify

= 1

\frac{d}{d x} (y^{2} + x)

\frac{d}{d x} (\frac{- e ^{x} x + 2 e ^{x}}{( 1 - x ) ^{2}})

sin (3 x), \frac{π}{3}

\frac{d y}{d x} = \frac{x}{y ^{2} 1 + x}

\int 2 e^{2 y} d y

What is the limit as x approaches-infinity of 1+e^x ?
The limit as x approaches-infinity of 1+e^x is 1