What is area f(x)=e^x,g(x)=cos(x),x=0,x= pi/2 ?

The answer to area f(x)=e^x,g(x)=cos(x),x=0,x= pi/2 is 2.81047…

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area f(x)=e^x,g(x)=cos(x),x=0,x= pi/2

area

f (x) = e^{x}, g (x) = cos (x), x = 0, x = \frac{π}{2}

2.81047 \dots

Solution steps

Apply the area formula:

\int_{0}^{\frac{π}{2}} ∣ e^{x} - cos (x) ∣ d x

Solve

\int_{0}^{\frac{π}{2}} ∣ e^{x} - cos (x) ∣ d x : 2.81047 \dots

The area is:

= 2.81047 \dots

y = x^{2} - 3 x, y = x

\int_{0}^{2} x (1 - x) d x

x \to - \infty lim (1 + e^{x})

\frac{d}{d x} (y^{2} + x)

\frac{d}{d x} (\frac{- e ^{x} x + 2 e ^{x}}{( 1 - x ) ^{2}})

What is area f(x)=e^x,g(x)=cos(x),x=0,x= pi/2 ?
The answer to area f(x)=e^x,g(x)=cos(x),x=0,x= pi/2 is 2.81047…