What is the integral from 0 to 3 of-6x^2 ?

The integral from 0 to 3 of-6x^2 is -54

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integral from 0 to 3 of-6x^2

\int_{0}^{3} - 6 x^{2} d x

- 54

Solution steps

\int_{0}^{3} - 6 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 6 \cdot \int_{0}^{3} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{3}

= - 6 [\frac{x ^{3}}{3}]_{0}^{3}

Compute the boundaries:

9

= - 6 \cdot 9

Simplify

= - 54

f (x) = 2 x^{3} - 5 x + 4, at x = - 1

\frac{1}{3 x ^{3}} + \frac{x ^{7}}{10}

x \to 2 + lim (x - 1)

\frac{5 s}{( s + 4 ) ^{3}}

\frac{\partial}{\partial x} (\frac{2 x}{( x ^{2} + y ^{2} )})

What is the integral from 0 to 3 of-6x^2 ?
The integral from 0 to 3 of-6x^2 is -54