What is (\partial)/(\partial y)(sin(3x-4y)) ?

The answer to (\partial)/(\partial y)(sin(3x-4y)) is -4cos(3x-4y)

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(\partial)/(\partial y)(sin(3x-4y))

\frac{\partial}{\partial y} (sin (3 x - 4 y))

- 4 cos (3 x - 4 y)

Solution steps

\frac{\partial}{\partial y} (sin (3 x - 4 y))

Treat

x

as a constant

Apply the chain rule:

cos (3 x - 4 y) \frac{\partial}{\partial y} (3 x - 4 y)

= cos (3 x - 4 y) \frac{\partial}{\partial y} (3 x - 4 y)

\frac{\partial}{\partial y} (3 x - 4 y) = - 4

= cos (3 x - 4 y) (- 4)

Simplify

= - 4 cos (3 x - 4 y)

\int \frac{1}{x ^{2} + 5} d x

x \to 2 lim (\frac{- 2}{x ( x - 2 )})

f (x) = \frac{e ^{x}}{4 x + 1}

\int \frac{3 x ^{2} + 2}{( x ^{3} + 2 x ) ^{2}} d x

y = \frac{2 x}{x + 1}, (1, 1)

What is (\partial)/(\partial y)(sin(3x-4y)) ?
The answer to (\partial)/(\partial y)(sin(3x-4y)) is -4cos(3x-4y)