What is the integral from-2 to 3 of (27)/(x^4) ?

The integral from-2 to 3 of (27)/(x^4) is diverges

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integral from-2 to 3 of (27)/(x^4)

\int_{- 2}^{3} \frac{27}{x ^{4}} d x

diverges

Solution steps

\int_{- 2}^{3} \frac{27}{x ^{4}} d x

Find undefined (singularity) points:

x = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{- 2}^{0} \frac{27}{x ^{4}} d x + \int_{0}^{3} \frac{27}{x ^{4}} d x

\int_{- 2}^{0} \frac{27}{x ^{4}} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

x y^{2} y^{^{'}} = y^{3} - 1 x^{3}

\frac{\partial}{\partial y} (\frac{- x}{( x + y ) ^{2}})

\int_{0}^{1} x 8 - x^{2} d x

(1 + ln (x) + \frac{y}{x}) d x = (7 - ln (x)) d y

x \to - 7 lim (\frac{1}{x + 7})

What is the integral from-2 to 3 of (27)/(x^4) ?
The integral from-2 to 3 of (27)/(x^4) is diverges