What is the solution for xy^2y^'=y^3-1x^3 ?

The solution for xy^2y^'=y^3-1x^3 is y=x\sqrt[3]{-3ln(x)+c_{1}}

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xy^2y^'=y^3-1x^3

x y^{2} y^{^{'}} = y^{3} - 1 x^{3}

Solution steps

x y^{2} y^{'} (x) = y^{3} - 1 x^{3}

Solve Bernoulli ODE:

\frac{\partial}{\partial y} (\frac{- x}{( x + y ) ^{2}})

\int_{0}^{1} x 8 - x^{2} d x

(1 + ln (x) + \frac{y}{x}) d x = (7 - ln (x)) d y

x \to - 7 lim (\frac{1}{x + 7})

[t]

What is the solution for xy^2y^'=y^3-1x^3 ?
The solution for xy^2y^'=y^3-1x^3 is y=x\sqrt[3]{-3ln(x)+c_{1}}