What is the d/(dv)(ae^v+b/v+c/(v^2)) ?

The d/(dv)(ae^v+b/v+c/(v^2)) is ae^v-b/(v^2)-(2c)/(v^3)

What is the first d/(dv)(ae^v+b/v+c/(v^2)) ?

The first d/(dv)(ae^v+b/v+c/(v^2)) is ae^v-b/(v^2)-(2c)/(v^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d v} (a e^{v} + \frac{b}{v} + \frac{c}{v ^{2}})

a e^{v} - \frac{b}{v ^{2}} - \frac{2 c}{v ^{3}}

Solution steps

\frac{d}{d v} (a e^{v} + \frac{b}{v} + \frac{c}{v ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d v} (a e^{v}) + \frac{d}{d v} (\frac{b}{v}) + \frac{d}{d v} (\frac{c}{v ^{2}})

\frac{d}{d v} (a e^{v}) = a e^{v}

\frac{d}{d v} (\frac{b}{v}) = - \frac{b}{v ^{2}}

\frac{d}{d v} (\frac{c}{v ^{2}}) = - \frac{2 c}{v ^{3}}

= a e^{v} - \frac{b}{v ^{2}} - \frac{2 c}{v ^{3}}

x y^{^{'}} - 2 y + y^{2} = 0

y^{^{''}} + 2 k y^{^{'}} + k^{4} y = 0

(9, 12), (- 2, - 17)

\int \frac{x ^{2}}{( x + 1 ) ( x + 2 ) ^{2}} d x

\int x^{2} e^{x y} d y

What is the d/(dv)(ae^v+b/v+c/(v^2)) ?
The d/(dv)(ae^v+b/v+c/(v^2)) is ae^v-b/(v^2)-(2c)/(v^3)
What is the first d/(dv)(ae^v+b/v+c/(v^2)) ?
The first d/(dv)(ae^v+b/v+c/(v^2)) is ae^v-b/(v^2)-(2c)/(v^3)