What is the derivative of 3x^3-x^2+1 ?

The derivative of 3x^3-x^2+1 is 9x^2-2x

What is the first derivative of 3x^3-x^2+1 ?

The first derivative of 3x^3-x^2+1 is 9x^2-2x

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\frac{d}{d x} (3 x^{3} - x^{2} + 1)

9 x^{2} - 2 x

Solution steps

\frac{d}{d x} (3 x^{3} - x^{2} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{3}) - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (1)

\frac{d}{d x} (3 x^{3}) = 9 x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (1) = 0

= 9 x^{2} - 2 x + 0

Simplify

= 9 x^{2} - 2 x

(- 8.2) (- 10.5)

y = (2 x - 1)^{2} ln (2 x - 1)

2 sin (π t)

f (x) = x^{4} - 2 x^{2} + 1, at x = - 2

y = 2 e^{x} cos (x), (0, 2)

What is the derivative of 3x^3-x^2+1 ?
The derivative of 3x^3-x^2+1 is 9x^2-2x
What is the first derivative of 3x^3-x^2+1 ?
The first derivative of 3x^3-x^2+1 is 9x^2-2x