What is the tangent of f(x)=x^4-2x^2+1,\at x=-2 ?

The tangent of f(x)=x^4-2x^2+1,\at x=-2 is y=-24x-39

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=x^4-2x^2+1,\at x=-2

tangent of

f (x) = x^{4} - 2 x^{2} + 1, at x = - 2

y = - 24 x - 39

Solution steps

Find the tangent point:

(- 2, 9)

Find the slope of

f (x) = x^{4} - 2 x^{2} + 1 : \frac{df ( x )}{d x} = 4 x^{3} - 4 x

Compute the slope of

f (x) = x^{4} - 2 x^{2} + 1

x = - 2 : m = - 24

Find the line with slope m=

- 24

and passing through

(- 2, 9) : y = - 24 x - 39

y = - 24 x - 39

y = 2 e^{x} cos (x), (0, 2)

\frac{d}{d x} (cos^{3} (4 x^{2}))

\frac{d}{d x} (ln (a x^{n}))

x \to \infty lim (5^{- x})

\frac{2 t}{4 + t ^{2}}

What is the tangent of f(x)=x^4-2x^2+1,\at x=-2 ?
The tangent of f(x)=x^4-2x^2+1,\at x=-2 is y=-24x-39