What is the derivative of 2sin(pit) ?

The derivative of 2sin(pit) is 2cos(pit)pi

What is the first derivative of 2sin(pit) ?

The first derivative of 2sin(pit) is 2cos(pit)pi

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derivative of

2 sin (π t)

2 cos (π t) π

Solution steps

\frac{d}{d t} (2 sin (π t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d t} (sin (π t))

Apply the chain rule:

cos (π t) \frac{d}{d t} (π t)

= cos (π t) \frac{d}{d t} (π t)

\frac{d}{d t} (π t) = π

= 2 cos (π t) π

f (x) = x^{4} - 2 x^{2} + 1, at x = - 2

y = 2 e^{x} cos (x), (0, 2)

\frac{d}{d x} (cos^{3} (4 x^{2}))

\frac{d}{d x} (ln (a x^{n}))

x \to \infty lim (5^{- x})

What is the derivative of 2sin(pit) ?
The derivative of 2sin(pit) is 2cos(pit)pi
What is the first derivative of 2sin(pit) ?
The first derivative of 2sin(pit) is 2cos(pit)pi