What is the integral from 5 to e^3 of 1/x ?

The integral from 5 to e^3 of 1/x is 3-ln(5)

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integral from 5 to e^3 of 1/x

\int_{5}^{e^{3}} \frac{1}{x} d x

3 - ln (5)

Solution steps

\int_{5}^{e^{3}} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{5}^{e^{3}}

Compute the boundaries:

3 - ln (5)

= 3 - ln (5)

y^{^{'}} = x e^{y}

\frac{\partial}{\partial y} (sin^{2} (y))

\frac{\partial}{\partial x} (x^{e^{x}})

(- 4) (12.2)

\frac{\partial}{\partial x} ((x^{9}) (y^{6}) + 7 (x^{5}) y)

What is the integral from 5 to e^3 of 1/x ?
The integral from 5 to e^3 of 1/x is 3-ln(5)