What is (\partial)/(\partial y)(sin^2(y)) ?

The answer to (\partial)/(\partial y)(sin^2(y)) is sin(2y)

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(\partial)/(\partial y)(sin^2(y))

\frac{\partial}{\partial y} (sin^{2} (y))

sin (2 y)

Solution steps

\frac{\partial}{\partial y} (sin^{2} (y))

Apply the chain rule:

2 sin (y) \frac{\partial}{\partial y} (sin (y))

= 2 sin (y) \frac{\partial}{\partial y} (sin (y))

\frac{\partial}{\partial y} (sin (y)) = cos (y)

= 2 sin (y) cos (y)

Use the Double Angle identity:

2 sin (x) cos (x) = sin (2 x)

= sin (2 y)

\frac{\partial}{\partial x} (x^{e^{x}})

(- 4) (12.2)

\frac{\partial}{\partial x} ((x^{9}) (y^{6}) + 7 (x^{5}) y)

\int \frac{2 x ^{2} - 4 x + 4}{3 + 2 x - x ^{2}} d x

y^{^{'}} = y - y^{2}

What is (\partial)/(\partial y)(sin^2(y)) ?
The answer to (\partial)/(\partial y)(sin^2(y)) is sin(2y)