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Popular >

y^'=xe^y

Solution

y^{^{'}} = x e^{y}

Solution

y = - ln (- \frac{x ^{2}}{2} - c_{1})

Solution steps

y^{'} (x) = x e^{y}

Solve separable ODE:

y = - ln (- \frac{x ^{2}}{2} - c_{1})

y = - ln (- \frac{x ^{2}}{2} - c_{1})

Popular Examples

(\partial)/(\partial y)(sin^2(y))

\frac{\partial}{\partial y} (sin^{2} (y))

(\partial)/(\partial x)(x^{e^x})

\frac{\partial}{\partial x} (x^{e^{x}})

slope of (-4)(12.2)slope

(- 4) (12.2)

(\partial)/(\partial x)((x^9)(y^6)+7(x^5)y)

\frac{\partial}{\partial x} ((x^{9}) (y^{6}) + 7 (x^{5}) y)

integral of (2x^2-4x+4)/(sqrt(3+2x-x^2))

\int \frac{2 x ^{2} - 4 x + 4}{3 + 2 x - x ^{2}} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=xe^y ?
The solution for y^'=xe^y is y=-ln(-(x^2)/2-c_{1})