What is the solution for (x^2+1)(dy)/(dx)+4xy=x ?

The solution for (x^2+1)(dy)/(dx)+4xy=x is y=(c_{1})/(4(x^4+2x^2+1))+1/4

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(x^2+1)(dy)/(dx)+4xy=x

(x^{2} + 1) \frac{d y}{d x} + 4 x y = x

y = \frac{c _{1}}{4 ( x ^{4} + 2 x ^{2} + 1 )} + \frac{1}{4}

Solution steps

(x^{2} + 1) \frac{d y}{d x} + 4 x y = x

Solve separable ODE:

y = \frac{c _{1}}{4 ( x ^{4} + 2 x ^{2} + 1 )} + \frac{1}{4}

y = \frac{c _{1}}{4 ( x ^{4} + 2 x ^{2} + 1 )} + \frac{1}{4}

\frac{( x )}{x + 1}

\int \frac{x}{x ^{4} + 8 x ^{2} + 17} d x

\frac{\partial}{\partial x} (y cos (x))

\int_{5}^{e^{3}} \frac{1}{x} d x

y^{^{'}} = x e^{y}

What is the solution for (x^2+1)(dy)/(dx)+4xy=x ?
The solution for (x^2+1)(dy)/(dx)+4xy=x is y=(c_{1})/(4(x^4+2x^2+1))+1/4