What is the derivative of sin(-4x) ?

The derivative of sin(-4x) is -cos(4x)*4

What is the first derivative of sin(-4x) ?

The first derivative of sin(-4x) is -cos(4x)*4

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\frac{d}{d x} (sin (- 4 x))

- cos (4 x) \cdot 4

Solution steps

\frac{d}{d x} (sin (- 4 x))

Simplify

sin (- 4 x) : - sin (4 x)

= \frac{d}{d x} (- sin (4 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (sin (4 x))

Apply the chain rule:

cos (4 x) \frac{d}{d x} (4 x)

= cos (4 x) \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= - cos (4 x) \cdot 4

(x^{2} + 1) \frac{d y}{d x} + 4 x y = x

\frac{( x )}{x + 1}

\int \frac{x}{x ^{4} + 8 x ^{2} + 17} d x

\frac{\partial}{\partial x} (y cos (x))

\int_{5}^{e^{3}} \frac{1}{x} d x

What is the derivative of sin(-4x) ?
The derivative of sin(-4x) is -cos(4x)*4
What is the first derivative of sin(-4x) ?
The first derivative of sin(-4x) is -cos(4x)*4