What is the tangent of y=sqrt(5x+6),(2,4) ?

The tangent of y=sqrt(5x+6),(2,4) is y= 5/8 x+11/4

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tangent of y=sqrt(5x+6),(2,4)

tangent of

y = 5 x + 6, (2, 4)

y = \frac{5}{8} x + \frac{11}{4}

Solution steps

Find the slope of

y = 5 x + 6 : \frac{d y}{d x} = \frac{5}{2 5 x + 6}

Compute the slope of

y = 5 x + 6

(2, 4) : m = \frac{5}{8}

Find the line with slope m=

\frac{5}{8}

and passing through

(2, 4) : y = \frac{5}{8} x + \frac{11}{4}

y = \frac{5}{8} x + \frac{11}{4}

\int (x + 3)^{2} sin (x) d x

\frac{d}{d x} (sin (- 4 x))

(x^{2} + 1) \frac{d y}{d x} + 4 x y = x

\frac{( x )}{x + 1}

\int \frac{x}{x ^{4} + 8 x ^{2} + 17} d x

What is the tangent of y=sqrt(5x+6),(2,4) ?
The tangent of y=sqrt(5x+6),(2,4) is y= 5/8 x+11/4