What is the solution for (18y^2-xy)dx+x^2dy=0 ?

The solution for (18y^2-xy)dx+x^2dy=0 is y= x/(18ln(x)+c_{1)}

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(18y^2-xy)dx+x^2dy=0

(18 y^{2} - x y) d x + x^{2} d y = 0

y = \frac{x}{18 ln ( x ) + c _{1}}

Solution steps

(18 y^{2} - x y) d x + x^{2} d y = 0

Solve Bernoulli ODE:

y = \frac{x}{18 ln ( x ) + c _{1}}

y = \frac{x}{18 ln ( x ) + c _{1}}

f (x) = x^{2} - 1, (- 4, 15)

ln (x + 5)

\frac{d}{d x} (cos (\frac{nπ x}{2}))

\int_{0}^{1} x \cdot 2 x d x

6^{2^{x^{2}}}

What is the solution for (18y^2-xy)dx+x^2dy=0 ?
The solution for (18y^2-xy)dx+x^2dy=0 is y= x/(18ln(x)+c_{1)}